Question

void myterminate () 
{
   cout << "terminate handler called";
}

int main (void) 
{
   set_terminate (myterminate);
   
   throw;  // throwing an exception. So, terminate handler should be invoked 
           // as no one is handling this exception.    
   getch();
   return 0;
}

But After executing this code, the output is:

terminate handler called + "Debug Error!" dialog box appears.

I am not sure why it is coming like this !!!! Please help.

Answer 1

Based on the MSDN documentation for set_terminate the new handler function must call exit() or abort() will be called:

The set_terminate function installs term_func as the function called by terminate. set_terminate is used with C++ exception handling and may be called at any point in your program before the exception is thrown. terminate calls abort by default. You can change this default by writing your own termination function and calling set_terminate with the name of your function as its argument. terminate calls the last function given as an argument to set_terminate. After performing any desired cleanup tasks, term_func should exit the program. If it does not exit (if it returns to its caller), abort is called.

For example:

void myterminate () 
{
   cout << "terminate handler called";
   exit(1);
}