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Home/ Questions/Q 1011953
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T09:52:16+00:00 2026-05-16T09:52:16+00:00

void trim(string &str) { string::iterator it = str.begin(); string::iterator end = str.end() – 1;

  • 0
void trim(string &str)
{
    string::iterator it = str.begin();
    string::iterator end = str.end() - 1;

    // trim at the starting
    for(; it != str.end() && isspace(*it); it++)
        ;
    str.replace(str.begin(), it, "");

    // trim at the end
    for(; end >= str.begin() && isspace(*end); end--)
        ;
    str.replace(str.end(), end, ""); // i get the out_of_range exception here
}

I want to trim a string of spaces. First I trip spaces from the starting and it works fine and then I find the positions of spaces from the end and try to remove it and it throws exception.

Why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T09:52:17+00:00Added an answer on May 16, 2026 at 9:52 am

    Changing a string invalidates iterators into the string. One way to fix this would be to modify the string only once. Incidentally, this might also be faster:

    void trim(std::string &str)
    {
        std::string::size_type begin=0;
        while(begin<str.size() && isspace(str[begin]))
          ++begin;
        std::string::size_type end=str.size()-1;
        while(end>begin && isspace(str[end]))
          --end;
        str = str.substr(begin, end - begin + 1)
    }
    
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