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Home/ Questions/Q 8631885
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T09:16:42+00:00 2026-06-12T09:16:42+00:00

void xstrcpy ( char *t, char *s ); void main(void ) { char source[

  • 0
void xstrcpy ( char *t, char *s );

void main(void ) {      
    char source[ ] = "Sayonara" ;
    char target[20] ;
    xstrcpy ( target, source ) ;   
    printf ( "\nsource string = %s", source);
    printf ( "\ntarget string = %s", target ) ; 
}

void xstrcpy ( char *t, char *s ) {  
    while ( *s != '\0' ){
        *t = *s ;    
        t++ ; s++ ;
    } 
    *t = '\0' ;
} 

this code gives output:

source string = Sayonara 
target string = Sayonara

But when I change char target[20]; to char target[8];, it gives:

source string =  target string = Sayonara

When I change char target[20]; to char target[4];, it gives:

source string = nara 
target string = Sayonara

When I change char target[20]; to char target[3];, it gives:

source string = nara 
target string = Sayonara

Why does the source value change, and target becomes array having size of string?

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  1. Editorial Team
    Editorial Team
    2026-06-12T09:16:42+00:00Added an answer on June 12, 2026 at 9:16 am

    When your target is shorter than required, it overwrites whatever data following it. In particular, when you make it 8, it overwrites with terminating zero the beginning of the source. When you make it 4, it overwrites source with the tail of the source string.

    This is what’s happening. Though this behaviour is not guaranteed, of course, being undefined.

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