Question

  - (void)methedName{
      if(){
        _type ^=0x1;
      }
    }

What does this mean?

Answer 1

Your question’s title and your code do different things.

0x1 means “1” interpreted as hexadecimal digits. That happens to be the same as 1 in decimal.

So _type =0x1 simply sets _type to 1.

^ means the XOR (exclusive-or) operator.

^= means compute the XOR of the left-hand side with the right-hand side and assign the result to the left-hand side. In other words, ios_type ^= 0x1 is the same as ios_type = ios_type ^ 0x1.

So ios_type ^= 0x1 toggles the 1 bit of ios_type.