Question

Want to ask what happens if I write the following and run the program.

new int[5]; // without assigning it to a pointer.

The compilation passed.

But will there be a 5 * sizeof(int) chunk of memory allocated?

What if it is an object?

new some_obj_[5]; // without assigning it to a pointer.

Will the constructor of some_obj_ be invoked?

Answer 1

new int[5];//without assigning it to a pointer.

Yes, there will be a 5*sizeof(int) chunk of memory allocated but inaccessible to you, since you didn’t save the pointer. You will have a memory leak.

new some_obj_[5];//without assigning it to a pointer.

Yes, there will be 5*sizeof(some_obj_) chunk of memory allocated but inaccessible to you, since you didn’t save the pointer. The default constructor for some_obj_ will be called 5 times. That should be trivial to verify. Depending on how some_obj_ is coded you may have a memory leak.