Question

Want to know, having a class without any annotation, how the jaxb unmarshall the xml data to class.

I found it can take the following

If I have an node “label” in the xml

I have “_label” field in the class and “getLabel” and “setLabel” method.

jaxb can unmarshall it sucsessully. Just want to know its default rule.

Answer 1

The following is from the JAXB 2 specification (JSR-222):

8.12 Default Mapping

This section describes the default
mapping of program elements. The
default mapping is specified in terms
of default annotations that are
considered to apply to a program
element even in their absence.

8.12.1 Java Identifier To XML Name

The following is the default mapping
for different identifiers:

• class name: a class name is mapped to an XML name by de capitalization
  using
  java.beans.Introspector.decapitalize(class
  name ).
• enumtype name: enumtype name is mapped to an XML name by de
  capitalization using
  java.beans.Introspector.decapitalize(enumtype
  name).
• A property name (e.g. address) is derived from JavaBean access method
  (e.g. getAddress) by JavaBean de
  capitalization of the JavaBean
  property name
  java.beans.Introspector.decapitalize(JavaBeanAcc
  essMethod)