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Asked: May 11, 20262026-05-11T10:26:52+00:00 2026-05-11T10:26:52+00:00

Was this an oversight? Or is it to do with the JVM?

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Was this an oversight? Or is it to do with the JVM?

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  1. 2026-05-11T10:26:53+00:00Added an answer on May 11, 2026 at 10:26 am

    Java does indeed have pointers–pointers on which you cannot perform pointer arithmetic.

    From the venerable JLS:

    There are two kinds of types in the Java programming language: primitive types (§4.2) and reference types (§4.3). There are, correspondingly, two kinds of data values that can be stored in variables, passed as arguments, returned by methods, and operated on: primitive values (§4.2) and reference values (§4.3).

    And later:

    An object is a class instance or an array.

    The reference values (often just references) are pointers to these objects, and a special null reference, which refers to no object.

    (emphasis theirs)

    So, to interpret, if you write:

    Object myObj = new Object(); 

    then myObj is a reference type which contains a reference value that is itself a pointer to the newly-created Object.

    Thus if you set myObj to null you are setting the reference value (aka pointer) to null. Hence a NullPointerException is reasonably thrown when the variable is dereferenced.

    Don’t worry: this topic has been heartily debated before.

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