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Home/ Questions/Q 489003
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T01:45:53+00:00 2026-05-13T01:45:53+00:00

We all know that 42 is the answer to everything , but it’s news

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We all know that 42 is the answer to everything, but it’s news to me that it is a valid credit card number.

Try entering ’42’ or ‘42176’ into this jQuery Validation testing page and click OK.

What’s going on? I thought this was supposed to be the de-facto validation library. Even Microsoft is using it now, but it thinks ’42’ and ‘42176’ are valid credit card numbers?! It’s not even doing a length check. Surely I’m not responsible for adding a length check too? It’s called ‘creditcard’ validator and not ‘luhn’ validator.

Edit: hitchhiker humor aside – how would I go about patching the validation plugin to check length. is that easy?

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  1. Editorial Team
    Editorial Team
    2026-05-13T01:45:53+00:00Added an answer on May 13, 2026 at 1:45 am

    This is probably because this validator merely checks that the number supplied satisfies the LUHN-10 algorithm (which 42 satisfies since 4*2 + 2 = 10 which is 0 modulo 10).

    A better validator should maybe check for a minimal number of digits.

    I’m not sure this corresponds to the very latest code from jQuery, but I found the snippet associated with credit card validation:

        // http://docs.jquery.com/Plugins/Validation/Methods/creditcard
        // based on http://en.wikipedia.org/wiki/Luhn
        creditcard: function(value, element) {
            if ( this.optional(element) )
                return "dependency-mismatch";
            // accept only digits and dashes
            if (/[^0-9-]+/.test(value))
                return false;
            var nCheck = 0,
                nDigit = 0,
                bEven = false;
    
            value = value.replace(/\D/g, "");
    
            for (n = value.length - 1; n >= 0; n--) {
                var cDigit = value.charAt(n);
                var nDigit = parseInt(cDigit, 10);
                if (bEven) {
                    if ((nDigit *= 2) > 9)
                        nDigit -= 9;
                }
                nCheck += nDigit;
                bEven = !bEven;
            }
    
            return (nCheck % 10) == 0;
        },
    

    … and as you see this merely check that all characters are digits and that LUHN-10 is satisfied, without any attention to a minial length.

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