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Home/ Questions/Q 514607
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:32:33+00:00 2026-05-13T07:32:33+00:00

We are evaluating IoC containers for C# projects, and both Unity and Castle.Windsor are

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We are evaluating IoC containers for C# projects, and both Unity and Castle.Windsor are standing out. One thing that I like about Unity (NInject and StructureMap also do this) is that types where it is obvious how to construct them do not have to be registered with the IoC Container.

Is there way to do this in Castle.Windsor? Am I being fair to Castle.Windsor to say that it does not do this? Is there a design reason to deliberately not do this, or is it an oversight, or just not seen as important or useful?

I am aware of container.Register(AllTypes... in Windsor but that’s not quite the same thing. It’s not entirely automatic, and it’s very broad.

To illustrate the point, here are two NUnit tests doing the same thing via Unity and Castle.Windsor. The Castle.Windsor one fails. :

namespace SimpleIocDemo
{
    using NUnit.Framework;
    using Castle.Windsor;
    using Microsoft.Practices.Unity;

    public interface ISomeService
    {
        string DoSomething();
    }

    public class ServiceImplementation : ISomeService
    {
        public string DoSomething()
        {
            return "Hello";
        }
    }

    public class RootObject
    {
        public ISomeService SomeService { get; private set; }

        public RootObject(ISomeService service)
        {
            SomeService = service;
        }
    }

    [TestFixture]
    public class IocTests
    {
        [Test]
        public void UnityResolveTest()
        {
            UnityContainer container = new UnityContainer();
            container.RegisterType<ISomeService, ServiceImplementation>();
            // Root object needs no registration in Unity
            RootObject rootObject = container.Resolve<RootObject>();
            Assert.AreEqual("Hello", rootObject.SomeService.DoSomething());
        }

        [Test]
        public void WindsorResolveTest()
        {
            WindsorContainer container = new WindsorContainer();
            container.AddComponent<ISomeService, ServiceImplementation>();

            // fails with exception "Castle.MicroKernel.ComponentNotFoundException: 
            // No component for supporting the service SimpleIocDemo.RootObject was found"
            // I could add
            // container.AddComponent<RootObject>();
            // but that approach does not scale
            RootObject rootObject = container.Resolve<RootObject>();
            Assert.AreEqual("Hello", rootObject.SomeService.DoSomething());
        }
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-13T07:32:33+00:00Added an answer on May 13, 2026 at 7:32 am

    Windsor does not support this out of the box, and this is a deliberate decision. See this answer for more details.

    However, the later versions can be really easily extended to support this scenario by lazily registering non-registered components, as they are requested.
    You’ll have to implement ILazyComponentLoader interface, which will take up like 5 lines of code. See here for an example.

    Despite that my suggestion in 2018 is the same as it was in 2009 – don’t do it unless in very specific scenarios where you have a very good reason to choose this approach over alternatives

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