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Home/ Questions/Q 998169
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:09:01+00:00 2026-05-16T07:09:01+00:00

We are interested in finding maximum number of attributes a node has in a

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We are interested in finding maximum number of attributes a node has in a XML document. My code is below using C#:

        XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.Load(@"C:\ABC.xml");
        XmlNode root = xmlDoc.DocumentElement;

        int nodeAttrCount = 0;
        foreach (XmlNode node in root)                            
            if (nodeAttrCount < node.Attributes.Count)
                nodeAttrCount = node.Attributes.Count;

We are interested is: do we have any thing better than this. Like any method or property which give us the same result or anyother option.

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:09:02+00:00Added an answer on May 16, 2026 at 7:09 am

    You can also use LINQ to XML:

    XElement el = XElement.Load("MyXML.xml");
    int maxAttr = el.DescendantNodesAndSelf().OfType<XElement>().Max(x => x.Attributes().Count());
    

    The above code traverses all the xml nodes (it works with nested nodes too) and get the maximum number of attributes.


    For .net 2.0:

    XmlDocument doc = new XmlDocument();
    doc.Load("MyXML.xml");
    int max = 0;
    foreach (XmlNode xmlNode in doc.SelectNodes("//*"))
       if (max < node.Attributes.Count)
           max = node.Attributes.Count;
    

    This is basically the same as your solution;
    the main difference is that it considers all nodes at every nesting level (using XPath navigation).

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