Question

We can write the same statement in two different ways as follows. I have a question with providing two outputs for the value of x as follows.

int x = 10;
x = x*2+5; // Here the value of x is 25.

x = 10;
x *= 2+5; // Here the value of x is 70.

It is clear that this is because,
1. In the first statemnt x is multiplied by 2 then add 5.
2. In the second statemnt add 5 to 2 together then multiplied by x.
But why is it acting like this?

Answer 1

See: Operator precedence in Java. * binds tighter than + which both are tighter than = or *=.