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Home/ Questions/Q 163653
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Asked: May 11, 20262026-05-11T11:36:18+00:00 2026-05-11T11:36:18+00:00

We have a Coverity bug for this line of code: snprintf( tempStr, size, testStrings[testID],

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We have a Coverity bug for this line of code:

snprintf( tempStr, size, testStrings[testID], A2DtoV(testResults[testID].value), A2DtoV(testResults[testID].min),A2DtoV(testResults[testID].max)); 

The error says:

non_const_printf_format_string: 'format string is not a string literal,  potential security vulnerability if user controlled' 

I changed testStrings to a const, but that didn’t do anything:

static const char *testStrings[] = {'1', ... etc}; 

Any ideas as to what this error is really saying?

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  1. 2026-05-11T11:36:18+00:00Added an answer on May 11, 2026 at 11:36 am

    Your code is fine.

    The issue is that if you pass a string that is user controlled as a printf format string, security bugs can arise.

    For instance, printf(userName);

    Where userName is supplied by the user, a user can pass ‘%s’, and get your function to start accessing data at a random address on the stack, which could result in a crash. printf will try to pop additional parameters off the stack, resulting in a stack corruption. Denial of service attack like this is probably the best case, information can be disclosed by getting printf to dump out values on the stack and there are even ways to get printf style functions to modify the return address on the stack.

    Since your strings are not user controlled, it is safe to ignore this message. The typical fix is to replace the printf example I gave with printf('%s', userName);, which would not appear to help in your case because the const strings appear to contain format strings.

    Wikipedia has more on format string vulnerabilities here: http://en.wikipedia.org/wiki/Format_string_vulnerabilities

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