We have a restriction that a class cannot act as a base-class for more than 7 classes.
Is there a way to enforce the above rule at compile-time?
I am aware of Andrew Koenig’s Usable_Lock technique to prevent a class from being inherited but it would fail only when we try to instantiate the class. Can this not be done when deriving itself?
The base-class is allowed to know who are its children. So i guess we can declare a combination of friend
classes and encapsulate them to enforce this rule. Suppose we try something like this
class AA {
friend class BB;
private:
AA() {}
~AA() {}
};
class BB : public AA {
};
class CC : public AA
{};
The derivation of class CC would generate a compiler warning abt inaccessible dtor. We can then flag
such warnings as errors using compiler tweaks (like flag all warnings as errors), but i would not like to rely on such techniques.
Another way, but to me looks rather clumsy is:-
class B;
class InheritanceRule{
class A {
public:
A() {}
~A() {}
};
friend class B;
};
class B {
public:
class C : public InheritanceRule::A
{};
};
class D : public InheritanceRule::A{};
The derivation of class D will be flagged as a compiler error, meaning all the classes to be derived should be derived inside class B. This will allow atleast an inspection of the number of classes derived from class A but would not prevent anyone from adding more.
Anyone here who has a way of doing it ? Better still if the base-class need not know who are its children.
NOTE: The class which acts as a base-class can itself be instantiated (it is not abstract).
Thanks in advance,
EDIT-1: As per Comment from jon.h, a slight modification
// create a template class without a body, so all uses of it fail
template < typename D>
class AllowedInheritance;
class Derived; // forward declaration
// but allow Derived by explicit specialization
template<>
class AllowedInheritance< Derived> {};
template<class T>
class Base : private AllowedInheritance<T> {};
// privately inherit Derived from that explicit specialization
class Derived : public Base<Derived> {};
// Do the same with class Fail Error
// it has no explicit specialization, so it causes a compiler error
class Fail : public Base<Fail> {}; // this is error
int main()
{
Derived d;
return 0;
}
I’m tired as crap, can barely keep my eyes open, so there’s probably a more elegant way to do this, and I’m certainly not endorsing the bizarre idea that a Base should have at most seven subclasses.
Comment from jon.h:
It doesn’t. But then neither did the OP’s original example.
To the OP: your revision of my answer is pretty much a straight application of Coplien’s “Curiously recurring template pattern”]
I’d considered that as well, but the problem with that there’s no inheritance relationship between a
derived1 : pubic base<derived1>and aderived2 : pubic base<derived2>, becausebase<derived1>andbase<derived2>are two completely unrelated classes.If your only concern is inheritance of implementation, this is no problem, but if you want inheritance of interface, your solution breaks that.
I think there is a way to get both inheritance and a cleaner syntax; as I mentioned I was pretty tired when I wrote my solution. If nothing else, by making RealBase a base class of Base in your example is a quick fix.
There are probably a number of ways to clean this up. But I want to emphasize that I agree with markh44: even though my solution is cleaner, we’re still cluttering the code in support of a rule that makes little sense. Just because this can be done, doesn’t mean it should be.
If the base class in question is ten years old and too fragile to be inherited from, the real answer is to fix it.