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We have a six sided die, with sides numbered 1 through 6.
The probability of first seeing a 1 on the n-th roll decreases as n increases.
I want to find the smallest number of rolls such that this probability is less than some given limit.
def probTest(limit):
prob = 1.0
n = 1
while prob > limit:
prob = (1/6)**n
n += 1
return n-1
What is wrong with my code?
The probably of rolling a one on the nth roll is 5/6^(n-1)*1/6, not 1/6^n.
1/6^n is the probability of rolling one on all n rolls.
The first n-1 rolls each have a 5/6 chance of not being one.
The nth roll has a 1/6th chance of being one.