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Home/ Questions/Q 8087403
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T18:45:51+00:00 2026-06-05T18:45:51+00:00

We have a table with tree structure like this: Id Desc ParentID === A

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We have a table with tree structure like this:

Id  Desc  ParentID
===
A    DescrA   NULL
B    DescrB   A
C    DescrC   A
D    DescrD   C
E    DescrE   C
F    DescrF   E

We need a query that returns the number of descendants (including subdescendants) of a specific ID, something like:

select count(descendants) from Tablex where id='A' --result = 5
select count(descendants) from Tablex where id='B' --result = 0
select count(descendants) from Tablex where id='C' --result = 3
select count(descendants) from Tablex where id='E' --result = 1

We have seen it would be made ‘easily’ with CTE but couldnt get the gist of it…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T18:45:54+00:00Added an answer on June 5, 2026 at 6:45 pm
    declare @T table
    (
      Id char(1),
      ParentId char(1)
    );
    
    insert into @T values
    ('A', NULL),
    ('B', 'A'),
    ('C', 'A'),
    ('D', 'C'),
    ('E', 'C'),
    ('F', 'E');
    
    declare @ParentId char(1);
    set @ParentId = 'A';
    
    with C as
    (
      select Id, ParentId
      from @T
      where ParentId = @ParentId
      union all
      select T.Id, T.ParentId
      from @T as T
        inner join C
          on T.ParentId = C.Id
    )
    select count(*)
    from C;
    
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