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Home/ Questions/Q 7854213
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T19:59:01+00:00 2026-06-02T19:59:01+00:00

We have different JRE implementation from 2 vendors one is Jrockit from BEA and

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We have different JRE implementation from 2 vendors one is Jrockit from BEA and other is from Sun.
In my project the document clearly states to use the Jrockit implementation from BEA. So i want to know the differences and upperhand of Jrockit over the standard sun JVM.

thanks
Punith

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  1. Editorial Team
    Editorial Team
    2026-06-02T19:59:02+00:00Added an answer on June 2, 2026 at 7:59 pm

    Firstly, BEA and Sun were both taken over by Oracle. So JRockit and HotSpot are now both Oracle products.

    JRockit started out as a faster JVM than Hotspot for server-side code, but a lot of work has been done since then to make Hotspot faster, so it is not clear if that still applies. The other thing that I recall is that JRockit has (had) a different heap sizing strategy. In particular, you didn’t need to provide a fixed upper bound for the heap. This could be a good thing or a bad thing, depending on your perspective.

    From a purely functional stand-point, JRockit and HotSpot implementations of the same Java baseline should be virtually identical.

    Here are some other resources (from a Google search):

    • “Comparison Between Sun JDK And Oracle JRockit”
    • JRockit JVM versus HotSpot JVM
    • Wikipedia’s JRockit page.
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