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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T11:26:58+00:00 2026-05-12T11:26:58+00:00

we have some C++ code that we need to create a make file in.

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we have some C++ code that we need to create a make file in. Each .h and .C pair create an object and then some objects are linked together to form a executable. Pretty standard stuff.

This non-gnu make command just builds all the files into object in a directory

%.o:%.C
    $(CC) $(CPFLAGS)  -c  $<

What this does is for each %.C file (ie every .C file) build a corresponding .o file.

Does anybody know how to do this with gmake?

Cheers

Mark

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  1. Editorial Team
    Editorial Team
    2026-05-12T11:26:58+00:00Added an answer on May 12, 2026 at 11:26 am

    The syntax you’ve shown is called a pattern rule in GNU make parlance, and it forms the corner stone of your solution. All you need is to add a way to get the list of .C files dynamically. Others have shown solutions that use $(shell) to do this, but that’s needlessly inefficient. I suggest you instead use $(wildcard), which is a GNU make built-in function designed for just this purpose:

    SRCS = $(wildcard *.C)
    OBJS = $(patsubst %.C,%.o,$(SRCS))
    foo: $(OBJS)
            $(CC) -o $@ $^
    
    %.o: %.C
            $(CC) $(CPFLAGS)  -c  $<
    

    If you are looking for something more concise, the following will work too:

    foo: $(patsubst %.C,%.o,$(wildcard *.C))
    

    This just eliminates the variables and takes advantage of the fact that GNU make provides a default %.o: %.C pattern rule, as well as a default rule for linking an executable together from a set of objects. Personally I would use the more verbose version as I find it easier to read and maintain, but to each their own.

    Hope that helps,

    Eric Melski

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