Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6172103
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T23:20:07+00:00 2026-05-23T23:20:07+00:00

We have tree structure like this: <Tree> <child1> <child2> <child2> </child1> </Tree> Here the

  • 0

We have tree structure like this:

<Tree>
   <child1>
         <child2>
         <child2>
   </child1>
</Tree>

Here the child2 can be at any level. Is there any way we can access child2 without knowing the hierarchy?

Thanks for all answer..is there any way in Castor?as we are using Castor for marshalling and unmarshilling

Here is a similar type of question: How to get a node from xml not knowing its level in flex?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T23:20:08+00:00Added an answer on May 23, 2026 at 11:20 pm

    Using XPath, you could do it something like this:

    XPath xpath = XPathFactory.newInstance().newXPath();
    NodeList child2Nodes= (NodeList) xpath.evaluate("//child2", doc, 
        XPathConstants.NODESET);
    

    Where doc is your org.w3c.dom.Document class.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a tree structure in memory that I would like to render in
I have a table in my database which stores a tree structure. Here are
I have a tree like structure created out of models using ForeignKey linkages. As
Assuming I have a tree structure UL --LI ---INPUT (checkbox) And I want to
I have a tree data structure that is L levels deep each node has
I have a sort of tree structure that represent a hierarchy of layers in
I have a table in SQL server that has the normal tree structure of
I have a tree of active record objects, something like: class Part < ActiveRecord::Base
I have an interesting situation and I'm wondering if there is a better way
I have the need to return tree like results from a single table. At

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.