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Home/ Questions/Q 966215
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:07:18+00:00 2026-05-16T02:07:18+00:00

We have variable $country , it can give ~50 different values. And variable $id

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We have variable $country, it can give ~50 different values.

And variable $id.

What we should do is to give a value for $id corresponding to $country value, like:

if ($country = 'USA') { $id = 'usa_type'; }
else if ($country = 'France') { $id = 'france_type'; }
else if ($country = 'German') { $id = 'german_type'; }
else if ($country = 'Spain') { $id = 'spain_type'; }
...
...
...
else if ($country = 'Urugway') { $id = 'urugway_type'; }
else { $id = 'undefined'; }

else if statement repeats everytime, and other data is typical.

Is there a way to make this code shorter?

Like:

[france]:'france_type;
[england]:'england_type;
...
[else]:'undefined'

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:07:18+00:00Added an answer on May 16, 2026 at 2:07 am

    You could just create $id from $country:

    $id = strtolower($country) . '_type';
    

    If you first need to determine the validity of $country, put all your countries in an array, then use in_array to determine if $country is valid:

    $countries = array('USA', 'France', 'Germany', 'Spain', 'Uruguay');
    if (in_array($country, $countries)) {
        $id = strtolower($country) . '_type';
    }
    
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