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Home/ Questions/Q 830343
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:01:44+00:00 2026-05-15T04:01:44+00:00

We need to write a email validation program in C. We are planning to

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We need to write a email validation program in C. We are planning to use GNU Cregex.h) regular expression.

The regular expression we prepared is

[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?

But the below code is failing while compiling the regex.

#include <stdio.h>
#include <regex.h>

int main(const char *argv, int argc)
{

    const char *reg_exp = "[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?";

int status = 1;

    char email[71];

    regex_t preg;

    int rc;

    printf("The regex = %s\n", reg_exp);

    rc = regcomp(&preg, reg_exp, REG_EXTENDED|REG_NOSUB);
    if (rc != 0)
    {
            if (rc == REG_BADPAT || rc == REG_ECOLLATE)
                    fprintf(stderr, "Bad Regex/Collate\n");
            if (rc == REG_ECTYPE)
                    fprintf(stderr, "Invalid Char\n");
            if (rc == REG_EESCAPE)
                    fprintf(stderr, "Trailing \\\n");
            if (rc == REG_ESUBREG || rc == REG_EBRACK)
                    fprintf(stderr, "Invalid number/[] error\n");
            if (rc == REG_EPAREN || rc == REG_EBRACE)
                    fprintf(stderr, "Paren/Bracket error\n");
            if (rc == REG_BADBR || rc == REG_ERANGE)
                    fprintf(stderr, "{} content invalid/Invalid endpoint\n");
            if (rc == REG_ESPACE)
                    fprintf(stderr, "Memory error\n");
            if (rc == REG_BADRPT)
                    fprintf(stderr, "Invalid regex\n");

            fprintf(stderr, "%s: Failed to compile the regular expression:%d\n", __func__, rc);
            return 1;
    }
    while (status)
    {
            fgets(email, sizeof(email), stdin);
            status = email[0]-48;

            rc = regexec(&preg, email, (size_t)0, NULL, 0);
            if (rc == 0)
            {
                    fprintf(stderr, "%s: The regular expression is a match\n", __func__);
            }
            else
            {
                    fprintf(stderr, "%s: The regular expression is not a match: %d\n", __func__, rc);
            }
    }

    regfree(&preg);

    return 0;
}

The regex compilation is failing with the below error.

The regex = [a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?
Invalid regex
main: Failed to compile the regular expression:13

What is the cause of this error? Whether the regex need to be modified?

Thanks,
Mathew Liju

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T04:01:44+00:00Added an answer on May 15, 2026 at 4:01 am

    Your problem is the four instances of the sequence (?. That’s meaningless – the ( starts a new sub-regex and you can’t have ? at the start of a regex.

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