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Home/ Questions/Q 6715117
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:34:34+00:00 2026-05-26T08:34:34+00:00

Web developer pastes my javascript code in their HTML My widget gets the page’s

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  • Web developer pastes my javascript code in their HTML
  • My widget gets the page’s url, and on the server, looks up the URL’s info, and returns a widget for that page.

How can I create that javascript?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:34:35+00:00Added an answer on May 26, 2026 at 8:34 am

    I don’t know of any tutorial, but this is what you could do.

    There are 2 pieces required for this to work.

    1. An initial script that gets loaded (the one the developer includes in their code)
    2. A second script that is generated on the server and is then loaded onto the page by the first script

    The first script will need to get the domain properties and pass those as url paramaters when requesting the second script.

    // script one
    // helperscript.js
    var head= document.getElementsByTagName('head')[0];
    var script= document.createElement('script');
    script.type= 'text/javascript';
    script.src= 'http://www.yourdomain.com/newscript.php?domain=' + 
         encodeURIComponent(location.hostname);
    head.appendChild(script);
    

    Then on the server (in this case i’ll use php), you just get the url paramater and do what you need with it. Just as an example I’ll make the new script run an alert function with the domain as its value.

    //php generating script
    //newscript.php
    <?php
    header('Content-Type: application/x-javascript', true); // so the browser knows this is javascript, even though the file has a .php extension
    ?> 
    alert(<?php echo $_GET['domain']; ?>);
    

    Thats it 🙂

    So your html page will look something like this.

    <html>
    <head>
        <script src="http://www.yourdomain.com/helperscript.js"></script>
    </head>
    <body>
    </body>
    </html>
    

    If you need more clarification leave a comment. Also I have not tested this code, so there may be a few bugs, but the method is correct.

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