Question

well the problem is that when I use this

    for($i=0;$i<count($losDatos);$i++)
    {
        $fecha=new DateTime($losDatos[$i]['fechautc']);
        echo $losDatos[$i]['lat'];
        echo $losDatos[$i]['lon'];
    }

I always get the server date instead of my field name

$losDatos[$i]['fechautc']=2011-03-18 18:47:00.0

the field from the database is Datetime type from SQL , what could be wrong?

previously in the script I used

$initDate=$losDatos[0]['fechautc'];

and it worked well

Answer 1

It’s possible that $losDatos[$i]['fechautc'] is null and so the DateTime is just showing the current time. Try dumping the array using print_r and see what’s there.