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Home/ Questions/Q 6387927
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T03:12:54+00:00 2026-05-25T03:12:54+00:00

We’ve got a base class for most of our domain object: public class AbstractEntity<TKey>

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We’ve got a base class for most of our domain object:

public class AbstractEntity<TKey>
{
    public virtual TKey ID { get; set; }
}

Now, for example, I’ve got class MobileOperator : AbstractEntity<int>.

What I want to do is to write generic equality comparer for all AbstractEntity descendants. And I want to create it like that:

var comparer = new AbstractEntityComparer<MobileOperator>();

I declare this comparer as following:

public class AbstractEntityEqualityComparer<TAbstractEntity, TId> : IEqualityComparer<TAbstractEntity>
    where TAbstractEntity : AbstractEntity<TId>

However, in this case I must explicitly tell the compiler that TId = int: new AbstractEntityComparer<MobileOperator, int>(). And if I put, say, long instead of int, it just wont compile. So, definitely, the compiler has a way to determine which type I use to create MobileOperator.

So is it possible to write comparer in a way that won’t make me write this redundant int thing all the time? And if yes, how can I do it?

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  1. Editorial Team
    Editorial Team
    2026-05-25T03:12:55+00:00Added an answer on May 25, 2026 at 3:12 am

    C# doesn’t do type inference based on constraints, so you need the explicit generic construction. See the this blog post by Eric Lippert for the details (and also an argument in the comments about why he’s wrong wrong wrong.)

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