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Editorial Team
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Asked: 2026-06-15T17:04:43+00:00

We’ve got an audit log table that stores each item’s price every day. Here’s

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We’ve got an “audit log” table that stores each item’s price every day. Here’s some sample data:

1 - Item 587 - $19.99 - 12/1/2012
2 - Item 587 - $19.99 - 12/2/2012
3 - Item 587 - $18.99 - 12/3/2012
4 - Item 587 - $18.99 - 12/4/2012
5 - Item 587 - $20.99 - 12/5/2012
6 - Item 587 - $19.99 - 12/6/2012
7 - Item 587 - $19.99 - 12/7/2012
8 - Item 587 - $17.99 - 12/8/2012
9 - Item 587 - $17.99 - 12/9/2012
10 - Item 587 - $17.99 - 12/10/2012

This works fine, however, this table is growing too quickly. We now need a T-SQL script to remove duplicate rows. The dataset after the script should be like this:

1 - Item 587 - $19.99 - 12/1/2012
3 - Item 587 - $18.99 - 12/3/2012
5 - Item 587 - $20.99 - 12/5/2012
6 - Item 587 - $19.99 - 12/6/2012
8 - Item 587 - $17.99 - 12/8/2012

It seems like a GROUP BY or DISTINCT is called for, but I’m unsure of how to start.

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1 Answer

  1. Editorial Team
    WITH DuplicateTableWithDupNumbers
as
(
    SELECT recid, itemid, price, date, 
        ROW_NUMBER() OVER (PARTITION BY itemid ORDER BY  dateDESC ) AS DupNumber
    FROM YourTable
)
delete from YourTable
where EXISTS
(
    SELECT 1 
    from DuplicateTableWithDupNumbers as dup 
    WHERE DupNumber > 1 AND dup.recid = yourtable.recid
)

    You can change your partition preferences as necessary. This will delete directly from your table in one query.

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