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Home/ Questions/Q 7550777
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T10:18:11+00:00 2026-05-30T10:18:11+00:00

What am I doing wrong here? // file main.cpp #include <iostream> #include <boost/numeric/ublas/vector.hpp> #include

  • 0

What am I doing wrong here?

// file main.cpp

#include <iostream>
#include <boost/numeric/ublas/vector.hpp>
#include <boost/numeric/ublas/matrix.hpp>
#include <boost/numeric/ublas/matrix_proxy.hpp>

namespace ublas = boost::numeric::ublas;

int main()
{
    ublas::vector<double> const v( 10 );
    ublas::matrix<double> m( 1, v.size() );
    ublas::matrix_row<ublas::matrix<double> > r( m, 1 );
    r = v;
    return 0;
}

This fails with message:

Check failed in file /usr/local/include/boost/numeric/ublas/functional.hpp at line 1370:
i < size_i
terminate called after throwing an instance of 'boost::numeric::ublas::bad_index'
  what():  bad index
Aborted

However, is there more laconic way to v into m at main.cpp?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T10:18:13+00:00Added an answer on May 30, 2026 at 10:18 am

    Did this not work?

    std::copy(v.begin(), v.end(), m.begin1());
    

    this will occupy the first v.size() elements of m with the value of v.

    The following code compiles and runs on my system (boost 1.48 and g++ 4.62)

    #include <boost/numeric/ublas/vector.hpp>
    #include <boost/numeric/ublas/matrix.hpp>
    #include <algorithm>
    
    int main()
    {
        boost::numeric::ublas::vector<int> v(10);
        boost::numeric::ublas::matrix<int> m(10,10);  //using v.size() also works
        std::copy(v.begin(), v.end(), m.begin1());
        return 0;
    }
    
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