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Home/ Questions/Q 6677775
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:09:48+00:00 2026-05-26T04:09:48+00:00

What am I missing here? I was playing with apply in Scheme, and wrote:

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What am I missing here? I was playing with apply in Scheme, and wrote:

(apply apply '(+ (1 2 3)))

The way I understand it, the first apply should do:

(apply + '(1 2 3))

and the second should do:

(+ 1 2 3)

But both Ypsilon and Gauche give about the same error (this is Ypsilon’s):

error: attempt call non-procedure: (+ 1 2 3)

backtrace:
  0  (apply apply '(+ (1 2 3)))
  ..."/dev/stdin" line 1

What have I failed to understand?

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:09:49+00:00Added an answer on May 26, 2026 at 4:09 am

    The problem with '(+ (1 2 3)) is that the + is quoted and thus interpreted as a symbol.

    You would have to use eval to get a value for the + symbol.

    In other words, what you are trying to do, is not going to work.

    Edit: Another option is quasiquote. Eg:

    (apply apply `(,+ (1 2 3))) ; => 6
    

    Or (without quasiquote)

    (apply apply (list + '(1 2 3))); => 6
    
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