Question

What are the default argv data types?

I want to grab 2 arguments from the cmd line and pass these arguments to fts_open with the return being set to fts_read. first being source folder path and second being output file path.

I previously passed argv + 1 and it sent the first argument, as well as the second argument, so the source and the output path was being included in the paths to traverse.

I only want to source path to be used for fts_open.

I know fts_open takes a NULL terminated list, I would like to create this from the first argument, the source. I had a few warnings before regarding different data types.

I just want to grab the first arg and store it in a char * and then create a NULL terminated list from this to pass to fts_open.

Answer 1

You need to copy the argument in question to a new list that only includes that argument and the final NULL pointer

int main(int argc, char **argv) {
    if (argc < 2) /* error */;
    char **copy = malloc(2 * sizeof *copy);
    copy[0] = malloc(strlen(argv[1]) + 1);
    if (!copy[0]) /* error */;
    strcpy(copy[0], argv[1]);
    copy[1] = NULL;

    whatever(copy/*, ... */);

    /* ... */

    free(copy[0]);
    free(copy);
}