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Home/ Questions/Q 532303
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:23:27+00:00 2026-05-13T09:23:27+00:00

What are the exact circumstances for which a return statement in Javascript can return

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What are the exact circumstances for which a return statement in Javascript can return a value other than this when a constructor is invoked using the new keyword?

Example:

function Foo () {
  return something;
}

var foo = new Foo ();

If I’m not mistaken, if something is a non-function primitive, this will be returned. Otherwise something is returned. Is this correct?

In other words, what values can something take to cause (new Foo () instanceof Foo) === false?

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:23:27+00:00Added an answer on May 13, 2026 at 9:23 am

    The exact condition is described on the [[Construct]] internal property, which is used by the new operator:

    From the ECMA-262 3rd. Edition Specification:

    13.2.2 [[Construct]]

    When the [[Construct]] property for a Function object F is
    called, the following steps are taken:

    1. Create a new native ECMAScript object.
    2. Set the [[Class]] property of Result(1) to "Object".
    3. Get the value of the prototype property of F.
    4. If Result(3) is an object, set the [[Prototype]] property of Result(1) to Result(3).
    5. If Result(3) is not an object, set the [[Prototype]] property of Result(1) to the original Object prototype object as
      described in 15.2.3.1.
    6. Invoke the [[Call]] property of F, providing Result(1) as the this value and
      providing the argument list passed into [[Construct]] as the
      argument values.
    7. If Type(Result(6)) is
      Object then return Result(6).
    8. Return Result(1).

    Look at steps 7 and 8, the new object will be returned only if the
    type of Result(6) (the value returned from the F constructor
    function) is not an Object.

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