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Editorial Team
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Asked: 2026-05-13T01:08:39+00:00

What code could I use in replace of <xsl:copy-of select=tag/> , that when applied

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What code could I use in replace of <xsl:copy-of select="tag"/>, that when applied to the following xml..

<tag>
  content
  <a>
    b
  </a>
</tag>

..would give the following result: ?

content
<a>
  b
</a>

I wish to echo out all the content therein, but excluding the parent tag

Basically I have several sections of content in my xml file, formatted in html, grouped in xml tags
I wish to conditionally access them & echo them out
For example: <xsl:copy-of select="description"/>
The extra parent tags generated do not affect the browser rendering, but they are invalid tags, & I would prefer to be able to remove them
Am I going about this in totally the wrong way?

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1 Answer

  1. Editorial Team

    Since you want to include the content part as well, you’ll need the node() function, not the * operator:

    <xsl:copy-of select="tag/node()"/>

    I’ve tested this on the input example and the result is the example result:

    content
<a>
  b
</a>

    Without hard-coding the root node name, this can be:

    <xsl:copy-of select="./node()" />

    This is useful in situations when you are already processing the root node and want an exact copy of all elements inside, excluding the root node. For example:

    <xsl:variable name="head">
  <xsl:copy-of select="document('head.html')" />
</xsl:variable>
<xsl:apply-templates select="$head" mode="head" />

<!-- ... later ... -->

<xsl:template match="head" mode="head">
  <head>
  <title>Title Tag</title>
  <xsl:copy-of select="./node()" />
  </head>
</xsl:template>
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