Question

What do the * and ** mean in this code?

def functionA(self, *a, **kw):
   # code here

Answer 1

Inside a function header:

* collects all the positional arguments in a tuple.

** collects all the keyword arguments in a dictionary.

>>> def functionA(*a, **kw):
       print(a)
       print(kw)


>>> functionA(1, 2, 3, 4, 5, 6, a=2, b=3, c=5)
(1, 2, 3, 4, 5, 6)
{'a': 2, 'c': 5, 'b': 3}

In a function call:

* unpacks a list or tuple into position arguments.

** unpacks a dictionary into keyword arguments.

>>> lis=[1, 2, 3, 4]
>>> dic={'a': 10, 'b':20}
>>> functionA(*lis, **dic)  #it is similar to functionA(1, 2, 3, 4, a=10, b=20)
(1, 2, 3, 4)
{'a': 10, 'b': 20}