What does >> do in this situation?
int n = 500;
unsigned int max = n>>4;
cout << max;
It prints out 31.
What did it do to 500 to get it to 31?
What does >> do in this situation? int n = 500; unsigned int max
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What does >> do in this situation?
int n = 500;
unsigned int max = n>>4;
cout << max;
It prints out 31.
What did it do to 500 to get it to 31?
Bit shifted!
Original binary of 500:
111110100
Shifted 4
000011111 which is 31!
This is equivilent of doing integer division by 16.
500/16 = 31
500/2^4 = 31
Some facts pulled from here: http://www.cs.umd.edu/class/spring2003/cmsc311/Notes/BitOp/bitshift.html (because blarging from my head results in rambling that is unproductive..these folks state it much cleaner than i could)
Shifting left using << causes 0’s to be shifted from the least significant end (the right side), and causes bits to fall off from the most significant end (the left side).
Shifting right using >> causes 0’s to be shifted from the most significant end (the left side), and causes bits to fall off from the least significant end (the right side) if the number is unsigned.
Bitshifting doesn’t change the value of the variable being shifted. Instead, a temporary value is created with the bitshifted result.