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Home/ Questions/Q 3434734
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T07:44:05+00:00 2026-05-18T07:44:05+00:00

What does it exactly mean when the Standard states $7.3.1.1/2 – The use of

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What does it exactly mean when the Standard states

$7.3.1.1/2 – “The use of the static
keyword is deprecated when declaring
variables in a namespace scope (see
annex D); the unnamed-namespace
provides a superior alternative.”

I have referred this but it does not cover what I am looking for.

Is there an example where the superiority is clearly demonstrated.

NB: I know about how unnamed namespaces can make extern variables visible in the translation unit and yet hide them from other translation units. But the point of this post is about ‘static namespace scope’ names (e.g global static variables)

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  1. Editorial Team
    Editorial Team
    2026-05-18T07:44:05+00:00Added an answer on May 18, 2026 at 7:44 am

    What does it exactly mean?

    Technically deprecated means that a future standard may remove the feature.

    In practice that isn’t going to happen, because of the need to support old code.

    So in practice it means, “strongly discouraged”.

    Example of superiority of unnamed namespace

    An unnamed namespace is generally superior because what you have in that namespace can have external linkage.

    In C++98 external linkage is necessary for things that can be template parameters, e.g., if you want to templatize on a char const*, it must be pointer to char that has external linkage.

    #include <iostream>
    
    // Compile with "-D LINKAGE=static" to see problem with "static"
    #ifndef LINKAGE
    #   define LINKAGE extern
    #endif
    
    template< char const* s >
    void foo()
    {
        std::cout << s << std::endl;
    }
    
    namespace {
        LINKAGE char const message[] = "Hello, world!";
    }  // namespace anon
    
    int main()
    {
        foo<message>();
    }
    

    That said, it’s a bit inconsistent that static isn’t also deprecated for functions.

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