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Home/ Questions/Q 618033
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:30:01+00:00 2026-05-13T18:30:01+00:00

What does it mean when a IllegalStateException is thrown when entering a synchronized block?

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What does it mean when a IllegalStateException is thrown when entering a synchronized block? I’m seeing this sometimes inside the run-method of a thread:

    public void run() {
        while (true) {
            int n = 0;
            synchronized (service) { // IllegalStateException
                n = processPendingRequests();
            }

            /*
             * If n > 0, we processed at least one element, in which case we
             * immediately check the queue again until it was empty.
             */
            if (n == 0) {
                sleep();
                continue;
            }
        }
    }

Can the service object cause the IllegalStateException? How?

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:30:02+00:00Added an answer on May 13, 2026 at 6:30 pm

    According to the Java Language Specification, the “synchronized” statement doesn’t throw an “IllegalStateException”. Therefore, either the Language Specification is wrong, you’re using a non-conforming JVM, or you’ve misinterpreted the behavior of your program — as far as I can see.

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