Question

What does public void set in Java, do? I’ve read that it ‘Sets the value of a named option’ so is it simply like a variable assignment in the form of a function or something? (Sorry, not really a Java programmer.)

Here is the code I’m analyzing:

public void set(String s, int value) {
  set(s, new Integer(value));
}

What’s inside it anyway? (the set(s,new Integer(value)) I’m thinking the two ‘sets’ are entirely different things.

Please Help. Sorry if this is a simple question, but I’m just trying to confirm my thoughts about the subject.

Answer 1

public void set(String s, int value) is a method declaration, which is followed by a method body inside { … }.

public void set(String s, int value)
\____/ \__/ \_/
   |     |   |
   |     |   '---- Method name
   |     |
   |     '-------- Method return type
   |
   '-------------- Access modifier

The line after the {:

set(s,new Integer(value))

is a method call, which calls the set-method with s and new Integer(value) as arguments.