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Home/ Questions/Q 6137015
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T17:40:29+00:00 2026-05-23T17:40:29+00:00

What does the below syntax represents? typedef UserArray<T,W,L,H> MyType; where: T = type of

  • 0

What does the below syntax represents?

typedef UserArray<T,W,L,H> MyType;

where:

  • T = type of an array element
  • W = width of an array element, 0 < W < 8
  • L = low bound of array index (preferably zero)
  • H = high bound of array index

Can anyone explain me using example for above declaration?

Does this concepts comes under STL?

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  1. Editorial Team
    Editorial Team
    2026-05-23T17:40:30+00:00Added an answer on May 23, 2026 at 5:40 pm

    UserArray is a class template that takes four template parameters.

    It’s probably defined like that:

    template<class T, int W, int L, int H> // parameter names might differ
    class UserArray
    {
        // ...
    };
    

    typedef is used to define aliases for types. This:

    typedef UserArray<T,W,L,H> MyType;
    

    Defines an alias for UserArray using the specified template parameters. T must be a type, and W, L and H must be compile-time integer constants. The resulting alias is called MyType, and using it is like using UserArray with the same parameters.

    Those techniques are used to simplify typing when a type is used a lot in many places. For instance, you can do this:

    typedef std::vector<int> IntVector;
    
    IntVector vect; // a vector of ints
    
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