Question

What does the second line inside this for loop means and what will be the codes representation in java?

private List<int> channels = new List<int>();
private List<byte> packet= new List<int>();

      for (i = 0; i < 2; i++)
            {
                channels.Add((int)packet[2 + (2 * i)]);
                channels[i] += ((int)packet[2 + (2 * i) + 1] << 8) & 0xFF00;
            }

Is this correct way to do above code in java?

            for (i = 0; i < 2; i++) {
            channels.add(packet.get(2 + (2 * i)));

            byte temp=channels.get(i);
            temp+=((packet.get(2 + (2 * i) + 1) << 8) & 0xFF00);
            channels.set(i, temp);
        }

Above worked fine but, this would do things better. Thanks to every one for response:

    for (i = 0; i < 2; i++) {
          channels.set(i, (byte) (packet.get(2 + (2 * i))+((packet.get(2 + (2 * i) + 1) << 8) & 0xFF00)));
}

Answer 1

What’s missing from Java is operator overloading. As such, if you use an ArrayList<Integer>, you’ll need to use get() and
set() instead of the [] operator.

Additionally, I don’t think you could have assigned a List<int> to a List<byte> in C#.