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Home/ Questions/Q 7496895
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T18:50:22+00:00 2026-05-29T18:50:22+00:00

What does the second to last line do here? It doesn’t seem to be

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What does the second to last line do here? It doesn’t seem to be assigning a variable, printing or anything but I’ve tried breaking the code in various ways and the line doublelist(somelist) seems to be necessary but I don’t know why.

def doubleList(list):
    i=0
    while i<len(list):
        list[i]=list[i]*2
        i=i+1

someList=[34,72,96]
doubleList(someList)
print someList
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  1. Editorial Team
    Editorial Team
    2026-05-29T18:50:23+00:00Added an answer on May 29, 2026 at 6:50 pm

    Functions can modify mutable arguments passed to them. The (poorly-named) list called “list” has (using a non-idiomatic style) each of its elements multiplied by two, in-place. For example:

    >>> def inplace(seq):
    ...     seq[0] = 5
    ... 
    >>> a = [1,2,3]
    >>> print a
    [1, 2, 3]
    >>> inplace(a)
    >>> a
    [5, 2, 3]
    
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