What does this do? Specifically, I have 3 fields out of 20 in ‘this’ object that I want to pass into the lambda. If I use [&] will it only take the 3 fields I use? And will they be passed by reference or value?
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What does this do? Specifically, I have 3 fields out of 20 in ‘this’ object that I want to pass into the lambda. If I use [&] will it only take the 3 fields I use? And will they be passed by reference or value?
Thanks
It specifies all (implicit) captures are captured by reference. That is, it behaves as if there exists a hidden reference member of the closure object, initialized by the actual captured object.
No, if you only capture members of the
thisobject, only thethispointer is captured (always by value).