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Home/ Questions/Q 561875
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:29:45+00:00 2026-05-13T12:29:45+00:00

What does this line do in Perl? my @parsedarray = ($rowcol =~ m/([A-Z]?)([0-9]+)/); $rowcol

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What does this line do in Perl?

my @parsedarray = ($rowcol =~ m/([A-Z]?)([0-9]+)/);

$rowcol is something like A1, D8 etc… and I know that the script somehow splits them up because the next two lines are these:

my $row = $parsedarray[0];
my $col = $parsedarray[1];

I just can’t see what this line does ($rowcol =~ m/([A-Z]?)([0-9]+)/); and how it works.

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:29:46+00:00Added an answer on May 13, 2026 at 12:29 pm

    The operator m// is a pattern match, basically a synonym of //. This matches an optional first letter and then 1 or more digits in row column. An array is returned as the result of the match with each element containing one of the matched groups (in brackets). Therefore $parsedarray[0] contains the letter (or nothing) and $parsedarray[1] contains the digits.

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