What does this line mean? I havn’t done C in a few years. Does it perform the operation in parens then make the int result a pointer??
b[0] = *(start + pos++);
What does this line mean? I havn’t done C in a few years. Does
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What does this line mean? I havn’t done C in a few years. Does it perform the operation in parens then make the int result a pointer??
b[0] = *(start + pos++);
Apparently
startis a pointer (or an array, which will decay to a pointer here anyway), which means that the result of the expression in()is a pointer, not anint. The*simply dereferences that pointer.The whole thing is equivalent to plain
b[0] = start[pos++], but for some reason some people prefer to use the obfuscated form as in your post.