Question

What does this method accomplish?

 URL aURL = new URL(myRemoteImages[position]);

myRemoteImages is a String list, with 4 different variables. And position is a

int position;

EDIT:
So if there anyway i could take the place of position with possibly something else?

possibly

 myRemoteImages{1,2,3,4};?

EDIT: i am using this to get the the URI for each image in the cahce…

public void getImagesfromCache(){
        ImageAdapter adapter = new ImageAdapter();

    String[] cachImages = myRemoteImages;

    try {   
     URL aURL2 = null;
     aURL2 = new URL(cachImages[position]);
     URI imageCacheUri = null;


     try {
            imageCacheUri = aURL2.toURI();
        } catch (URISyntaxException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        if(new File(new File(this.getApplicationContext().getCacheDir(), "thumbnails"),"" + imageCacheUri.hashCode()).exists()){
            Log.v("FOUND", "Images found in cache! Now being loaded!");
            String cacheFile = this.getApplicationContext().getCacheDir() +"/thumbnails/"+ imageCacheUri.hashCode();
            ImageView i = new ImageView(this.getApplicationContext());
            FileInputStream fis = null;
            try {
                fis = new FileInputStream(cacheFile);
            } catch (FileNotFoundException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

            Bitmap bm = BitmapFactory.decodeStream(fis);

             i.setImageBitmap(bm);
             putBitmapInDiskCache(imageCacheUri, bm);

             Log.v("Loader", "Image saved to cache");

             ((Gallery) findViewById(R.id.gallery))
              .setAdapter(new ImageAdapter(MainMenu.this));
        }

    } catch (MalformedURLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

As you see where position is used, how could i go about another way to return the URL’s to get the images in the cache?

Could i possibly store each URI in a SharePreference and fetch them in onCreate()??

Answer 1

It creates a URL object, from the url string specified by the element within the array (myRemoteImages) at the specific position.

The following syntax creates a URL object

URL aURL = new URL(<a string describing a URL>);

The following syntax gets the String value at the specified position

myRemoteImages[position]

So, to get a URL for each position, you could do

URL url1 = new URL(myRemoteImages[0]);
URL url2 = new URL(myRemoteImages[1]);
URL url3 = new URL(myRemoteImages[2]);
URL url4 = new URL(myRemoteImages[3]);

It would be far better though to have an array of URLs though. So it would be

URL [] urls = new URL[myRemoteImages.length];
for (int i = 0; i < myRemoteImages.length; i++) {
   urls[i] = myRemoteImages[i];
}

With this array of URLs, even though you know there are only 4 images, it can be extended easily without having to change any code. Hard coding is VERY bad, and will usually lead to errors in the long run.