What exactly does putting extern "C" into C++ code do?
For example:
extern "C" {
void foo();
}
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extern "C"makes a function-name in C++ have C linkage (compiler does not mangle the name) so that client C code can link to (use) your function using a C compatible header file that contains just the declaration of your function. Your function definition is contained in a binary format (that was compiled by your C++ compiler) that the client C linker will then link to using the C name.Since C++ has overloading of function names and C does not, the C++ compiler cannot just use the function name as a unique id to link to, so it mangles the name by adding information about the arguments. A C compiler does not need to mangle the name since you can not overload function names in C. When you state that a function has
extern "C"linkage in C++, the C++ compiler does not add argument/parameter type information to the name used for linkage.Just so you know, you can specify
extern "C"linkage to each individual declaration/definition explicitly or use a block to group a sequence of declarations/definitions to have a certain linkage:If you care about the technicalities, they are listed in section 7.5 of the C++03 standard, here is a brief summary (with emphasis on
extern "C"):extern "C"is a linkage-specificationAll function types, function names and variable names have a language linkageSee Richard’s Comment: Only function names and variable names with external linkage have a language linkageextern "C"is ignored for class membersSee Richard’s comment:extern "C"forces a function to have external linkage (cannot make it static)staticinsideextern "C"is valid; an entity so declared has internal linkage, and so does not have a language linkage