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Editorial Team
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Asked: 2026-06-16T01:21:58+00:00

What I am trying to do is echo out based on the $_GET[‘page’] variable

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What I am trying to do is echo out based on the $_GET[‘page’] variable however its echoing this out for all of my navigation menu’s. How can I only have it use the page I am on? This is only the php part of it, the actual html code goes below each line however for simplicity I did not include it

<?php if($_GET['page'] == 'user_edit' || 'NULL'){ echo "<li class=\"current\">"; } else{ echo "<li>";} ?>
<?php if($_GET['page'] == 'manage' || 'add' || 'ftp'){ echo "<li class=\"current\">"; } else{ echo "<li>";} ?>
<?php if($_GET['page'] == 'bugs' || 'support' || 'notifications'){ echo "<li class=\"current\">"; } else{ echo "<li>";} ?>
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1 Answer

  1. Editorial Team

    It does not work like this. Your conditions are evaluated as:

    if ( ( $var == 'foo' ) || ( 'bar' ) || ( 'baz' ) )

    Note the grouping above. All three are separate expressions. It does not mean “if $var equals ‘foo’, ‘bar’ or ‘baz'”, it means “if $var equals ‘foo’ is true or ‘bar’ is true or ‘baz’ is true”.

    And 'bar' is always true.

    You need:

    if ($var == 'foo' || $var == 'bar' || $var == 'baz')

    or

    if (in_array($var, array('foo', 'bar', 'baz'))
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