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Home/ Questions/Q 7575067
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T16:35:38+00:00 2026-05-30T16:35:38+00:00

What I am trying to do is getting the same result as clicking on

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What I am trying to do is getting the same result as clicking on this following submit button.

<input id="submit_http:" class="add_submit" type="button" onclick="return dex.forms.form_ajax_submit(this,function(res) { alert('posting failed'); },function(res) { alert('posting success'); });" value="Next" name="submit_http:">

I was trying to do it like that:

$('.NextButton').click(function () {
    dex.forms.form_ajax_submit(document.getElementsByName('submit_http:'),
        function(res) { 
            alert('posting failed');
        }, 
        function(res) { 
            alert('posting success'); 
        });
});

But looks like document.getElementsByName is not returning the same result
as the submit button ‘this’
How can I solve this issue?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T16:35:40+00:00Added an answer on May 30, 2026 at 4:35 pm

    The only actual mistake you made was using the function document.getElementsByName, because it returns an array of elements (as indicated by the plural). What you need is a single element.

    Either access the first element of the array by using:

    document.getElementsByName('submit_http:')[0]
    

    or use the already recommended and more precise function:

    document.getElementById('submit_http:')
    
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