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Home/ Questions/Q 9239041
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T07:53:48+00:00 2026-06-18T07:53:48+00:00

What I have is this struct Record { unsigned char cat; unsigned char len[2]={0x00,

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What I have is this

struct Record
{
unsigned char cat;
unsigned char len[2]={0x00, 0x1b};  // can't put short here because that 
                                   // whould change the size of the struct
unsigned char dat[253];
};
Record record;
unsigned short recordlen = *((unsigned short*)record.len);

This result in recordlen=0x1b00 instead of 0x001b

Same with *reinterpret_cast<unsigned short*>(record.len)

Can you explain why ? How should I be doing this ?

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  1. Editorial Team
    Editorial Team
    2026-06-18T07:53:49+00:00Added an answer on June 18, 2026 at 7:53 am

    Can you explain why?

    Because you cannot assume a specific endianness of your computer architecture.

    The natural follow-up question is what do you do about it. Fortunately, you can force a specific byte order by calling one of these functions htonl, htons, ntohl, or ntohs. They work regardless of the computer architecture on which you run them:

    On the sending end, you convert from host order to network order; on the receiving end, you convert from network order to host order.

    // Sending end
    unsigned short recordlen = calculate_len();
    *reinterpret_cast<unsigned short*>(record.len) = htons(recordlen);
    
    // Receiving end
    unsigned short recordlen = ntohs(*reinterpret_cast<unsigned short*>(record.len));
    
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