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Home/ Questions/Q 9014243
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T03:27:43+00:00 2026-06-16T03:27:43+00:00

what i need to do is: Check time at 1st point Check time at

  • 0

what i need to do is:

  1. Check time at 1st point

  2. Check time at 2nd point

  3. Calculate if the difference between times
    is less then a timeout i have (0.5 seconds)

tried this :

>>> from time import time
>>> a=time
>>> b=time
>>> a-b
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for -: 'builtin_function_or_method' and   builtin_function_or_method'

but im getting an error.

Please advice.

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  1. Editorial Team
    Editorial Team
    2026-06-16T03:27:44+00:00Added an answer on June 16, 2026 at 3:27 am

    This is actually very easy to do:

    from time import time
    
    time_1 = time()
    # do something
    time_2 = time()
    if time_2 - time_1 < .5:
        #do something
    
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