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Home/ Questions/Q 3353984
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T02:13:03+00:00 2026-05-18T02:13:03+00:00

What I need to have happen: PHP needs to launch an server app which

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What I need to have happen: PHP needs to launch an server app which has root permissions running in the background. All of this should be silent.

-Sudo is needed to allow php to perform an op that requires root permissions.

-Screen is required to allow the app to run outside the scope of the webpage which started the process.

-Expect is needed so that screen has a pts in which to run

-Sh is needed because whatever starts running needs to be backgrounded, presumably with the & operator. It would also need to pipe any output to /dev/null/since I don’t want my PHP page returning anything. This is probably negotiable somehow if somebody can think of a better way to do the call in PHP (fork…?)

As an example, the script I tried to use was:

#!/usr/bin/expect -f
spawn sh ( screen -t srcds /usr/local/srcds_l/startserv )& > /dev/null
exit 0

For reference I am trying to start a Counter-Strike Source server, and startserv is the name of the C code which handles launching the server and collecting its output. Can anybody correct my syntax for that snippet, or tell me why its the wrong thing to do?

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  1. Editorial Team
    Editorial Team
    2026-05-18T02:13:03+00:00Added an answer on May 18, 2026 at 2:13 am

    This situation was eventually solved by simply making the process daemonize itself using a fork and process group control and then just having PHP do a system call with a sudo in it.

    I had another similar situation to eventually found

    unbuffer -p
    

    which uses screen internally, and does the kind of work that I was initially thinking of having screen expect and sh do.

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