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Home/ Questions/Q 5839275
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T11:33:45+00:00 2026-05-22T11:33:45+00:00

What I understand from the documentation is that UnsupportedEncodingException can only be thrown if

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What I understand from the documentation is that UnsupportedEncodingException can only be thrown if I specify a wrong encoding as the second parameter to URLDecoder.decode(String, String) method. Is it so? I need to know cases where this exception can be thrown.

Basically, I have this code segment in one of my functions:

if (keyVal.length == 2) {
    try {
        value = URLDecoder.decode(
            keyVal[1],
            "UTF-8");
    } catch (UnsupportedEncodingException e) {
          // Will it ever be thrown?
    }
}

Since I am explicitly mentioning “UTF-8”, is there any way this exception can be thrown? Do I need to do anything in the catch block? Or, if my understanding is completely wrong, please let me know.

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  1. Editorial Team
    Editorial Team
    2026-05-22T11:33:46+00:00Added an answer on May 22, 2026 at 11:33 am

    It cannot happen, unless there is something fundamentally broken in your JVM. But I think you should write this as:

    try {
        value = URLDecoder.decode(keyVal[1], "UTF-8");
    } catch (UnsupportedEncodingException e) {
        throw new AssertionError("UTF-8 is unknown");
        // or 'throw new AssertionError("Impossible things are happening today. " +
        //                              "Consider buying a lottery ticket!!");'
    }
    

    The cost of doing this is a few bytes of code that will “never” be executed, and one String literal that will never be used. That a small price for the protecting against the possibility that you may have misread / misunderstood the javadocs (you haven’t in this case …) or that the specs might change (they won’t in this case …)

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