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Home/ Questions/Q 6587895
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T16:58:39+00:00 2026-05-25T16:58:39+00:00

what I want is a sort of a mouse-trail effect, when you hover up

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what I want is a sort of a mouse-trail effect, when you hover up or down the divs. But if you hover the mouse too fast a few times and then stop, the effect keeps repeating on it’s own.

How can I solve this? I think I need some kind of a de-queue thing like with animate option, but for the fadeTo function. any ideas?

$(".test").mouseover(function(e) {
  $(this).fadeTo(200, 1);
}).mouseout(function(e) {
  $(this).fadeTo(200, 0.3);
});
.test {
  padding: 5px;
  width: 200px;
  color: #ffffff;
  font-weight: bold;
  background: #000000;
  opacity: 0.3;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.6.3/jquery.min.js"></script>
<div class='test'>asd</div>
<div class='test'>asd</div>
<div class='test'>asd</div>
<div class='test'>asd</div>
<div class='test'>asd</div>
<div class='test'>asd</div>
<div class='test'>asd</div>
<div class='test'>asd</div>
<div class='test'>asd</div>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T16:58:40+00:00Added an answer on May 25, 2026 at 4:58 pm

    You can use the .stop method to stop previous animations. If you pass in true as an argument, it will also clear queued animations.

    If I’ve understood what you’re looking for correctly, then what you want is this (you said you want a “mouse trail”, which I’m taking to mean you don’t want the previous animation to stop as soon as the mouse leaves that element, hence only the one call to .stop):

    $(".test").mouseover(function(e){
        $(this).stop(true).fadeTo(200,1);
    }).mouseout(function(e){
        $(this).fadeTo(200,0.3);
    });
    

    You can see that running here.

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