Question

What I want is, I think, relatively simple:

> Bin = <<'Hello.world.howdy?'>>. > split(Bin, '.'). [<<'Hello'>>, <<'world'>>, <<'howdy?'>>] 

Any pointers?

Answer 1

There is no current OTP function that is the equivalent of lists:split/2 that works on a binary string. Until EEP-9 is made public, you might write a binary split function like:

split(Binary, Chars) ->     split(Binary, Chars, 0, 0, []).  split(Bin, Chars, Idx, LastSplit, Acc)   when is_integer(Idx), is_integer(LastSplit) ->     Len = (Idx - LastSplit),     case Bin of         <<_:LastSplit/binary,          This:Len/binary,          Char,          _/binary>> ->             case lists:member(Char, Chars) of                 false ->                     split(Bin, Chars, Idx+1, LastSplit, Acc);                 true ->                     split(Bin, Chars, Idx+1, Idx+1, [This | Acc])             end;         <<_:LastSplit/binary,          This:Len/binary>> ->             lists:reverse([This | Acc]);         _ ->             lists:reverse(Acc)     end.